Question

A 12 PF capacitor is connected to 50 Volt battery how much electrostatic energy is stored in capicator ? ​

Answer 1

${\bold{\underline{\underline{Answer:}}}}$

Solution : We have C = 12 PF = $12\times {10}^{-12}F$

$\implies$ V = 50V

$\implies$ Energy stored in the capacitor

$\implies$ $\frac{1}{2}\times\:CV^{2}$

$\implies \frac{1}{2}\times12\times10^{-12}\times(50)^{2}$

$\implies6\times10^{-12}\times25\times10^{2}$

$\implies150\times10^{-10}$

$\implies1.5\times{10}^{-8}J$

Answer 2

The total energy of capacitor is E=

2

1

CV

2

=

2

1

×12×10

−12

×50

2

=1.5×10

−8

J