Question

A 12 PF capacitor is connected to a 50V battery.How much electro static energy is stored in the capacitor?

(A) 15×10^-9 J
(B) 15×10^-3 J
(C) 15×10^-4 J
(D) 15×10^-12 J​

Answer 1

$\huge{\underline{\tt{\red{Answer-}}}}$

Capacitor of the capacitance, C = 12 pF =$12 \times 10^ {- 12}$ F

Potential difference, V = 50 V

Electrostatic energy stored in the capacitor is given by the relation,

$E= \dfrac{1}{2}Cv^2$

$\implies E=\dfrac{1}{2}\times12\times10^{-2}\times (50)^2$

$\implies E= 1.5 \times 10^{-8}$

Therefore, the electrostatic energy stored in the capacitor is $1.5 \times 10^{-8}$ J