Question

a 12 volt battery is connected across a load having a resistance of 40 ohm determine the current flowing in the load the power consumed and the energy dissipated in 2 minutes​

Answer 1

V=12Volt

R=40ohm

so, current

I=V/R

I=12/40

I=0.3Ampere

now,

Power=V*I

P=12*0.3

P=3.6watt

P=3.6/1000 =0.0036kwatt

now, for energy dissipated in two minutes

E=P*t

E=0.0036*2/60=0.0012kwatthr

Answer 2

Answer:

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