Question

A 12 volt battery is connected to 10ohm and 15ohm resistor.which are connected in parallel?
a)Draw the circuit diagram including ammeter and switch
b)Resulted resistance
c)Total intensity of current

Answer 1

Answer:

A) B) C)

Explanation:-

Answer 2

Answer:

The resultant resistance in parallel combination is 6Ω and the current through the circuit is 2A.

Explanation:

Given the voltage of battery, $V=12 V$

Resistances of resistors, $R_{1} =10\Omega$ and $R_{2} =15\Omega$

When the resistors are connected in parallel, the equivalent resistance is given by $\frac{1}{R} =\frac{1}{R_{1}}+\frac{1}{R_{2}}$

Substituting the values, $\frac{1}{R} =\frac{1}{10}+\frac{1}{15}$

$=\frac{3+2}{30}=\frac{5}{30}=\frac{1}{6}$  

Therefore, the resultant resistance of the combination of the resistors connected in parallel is 6Ω.

According to the Ohm's law, the voltage is directly proportional to the current flowing through a conductor, i.e.,

$V\propto I\implies V=IR$

where R is the proportionality constant, called resistance.  

Thus the current through the circuit is given by

$I=\frac{V}{R} =\frac{12}{6}=2A$

Therefore, the current through the circuit is 2A.

The circuit diagram  including ammeter and switch is attached.