Question

A 120 kg motorbike plus 80 kg rider is to accelerate from zero to 5 m S^-2 in 0.8 S. Estimate the average force required.​

Answer 1

Explanation:

m = 120kg + 80kg = 200kg

A1 = 0m/s²

A2 = 5m/s²

t = 0.8sec

F = ma ( Newton's second law of motion)

F1 = (200)(0)

= 0N ----(1)

F2 = (200)(5)

=. 1000N ----(2)

now, (1)+(2)/2 -----> average

= 0+1000/2

= 1000/2 = 500N ...:)!):) might help you