A 120 ohm resister is in series with an unkown resister the voltage drop across the unkown resister is 12v and the power dissipated by the 120ohm resister is 4.8w caluclate the value of the unkown resister.
Answers
Answer:
okay, I don't have much time to do the working but I can tell you how to answer this question.
we know
the resistance of the resistor ( we can name it R1 )
the power by this same resistor (R1)
we know the voltage across the unknown resistor ( we can call it R2 )
we are supposed to find the resistance of the unknown resistor
Another information that we are provided with is that the two resistors are in series which means that the current stays the same in series.
So, provided with this information we are to first find the current in the resistor R1
using
Power = i^2 × R
therefore we find the value of i from here which will be the same in resistor R2
Now that we have the value of i and the voltage in the unknown resistor. Using the formula
R= V/ i
Then after substituting the values you will get the value if the unknown resistance ..
I really hope it helps you ..
Please mark me as the brainliest.