A 120 v lamp-dimming circuit is controlled by a rheostat and protected from excessive current by a 3 a fuse. To what minimum resistance value can the rheostat be set without blowing the fuse? Assume a lamp resistance of 20 ohms.
a. 40
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Given in the question :-
R₂ = 20 Ω
V = 120
I = 3 A
Refer to the attachment .
Now , We know the formula.
v = I × R
R = V/I
R₁ + R₂ = V/I
R₁ + R₂ = 120/3
R₁ + 20 = 40
R₁ = 20 Ω
Hence the minimum resistance is 20 Ω.
Hope it Helps :-)
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