Question

a 1200 kg bicycle moving at 40 m/s westward collides with a 1100 kg vehicle moving a certain velocity in the opposite direction. After the collision of 1200 kg vehicle attains a velocity of 45 m/s westward while the 1,100 kg vehicle 35 m/s eastward find the velocity of 1100 ground vehicles before the collision​

Answer 1

Explanation:

using conservation of momentum

U1=40m/s

V1=45m/s

U2=?

V2=35m/s

m1v1+m2v2=m1u1+m2u2

1200*45+1100*35=1200*40+1100*u2

54000+38500=48000+1100u2

1100u2=92500-48000

1100u2=44500

u2=40.4m/s