A 1200 kg car traveling North at 20.0 m/s collides with a 1400 kg car traveling South at 22.0 m/s. The two cars collide and entangle. What is the resulting velocity of the wreckage?
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mass of the car 1, m1 = 1200 kg
initial velocity of the car, u1 = 20 m/s
mass of the car 2, m2 = 1400 kg
initial velocity of the car, u2 = 22 m/s
after the collision, the two car move together
Using momentum conservation along north south direction
m1u1 + m2u2 = ( m1 + m2 )V
1200 ( 20 ) + 1400 ( 22 ) = ( 1200 + 1400 ) V
24000 + 30800 = 2600 V
54800 = 2600 V
V = 2600/54800
V = 0.0474 m/s
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