Question

A 1200mm long bar of 30mm diameter is subjected to an axial push of 600KN
along its length. Calculate lateral strain if E=2 x 105 N/mm2 and p=0.3​

Answer 1

Step-by-step explanation:

Data: d=30 mm, L=200 mm, P =60 kN, δL=0.09 mm, δd = 0.0039 mm Calculate: μ and E

A=πd24=π×3024=706.858mm2

E=PLAδL=60×103×200706.858×0.09=188628.08N/mm2

E=1.89N/mm2

μμμ= Lateral Strain Linear Strain =(δdd)(δLL)=(0.003930)(0.09200)=0.29=0.29

Answer 2

Step-by-step explanation:

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