Question

A 120g mass has a velocity v=(2i + 5j ) m/s at a certain instance . its K.E is?​

Answer 1

Explanation:

V

KE=1/2mv²

KE=29*.120=3.48

Answer 2

The kinetic energy of the object is 1.74 Joules.

Explanation:

It is given that,

Mass of the object, m = 120 g = 0.12 kg

Velocity of the object, $v=(2i+5j)\ m/s$

The resultant magnitude of velocity, $|v|=\sqrt{2^2+5^2} =5.385\ m/s$

The kinetic energy is possessed by an object by virtue of its movement. It is given by the relation as :

$E=\dfrac{1}{2}mv^2$

$E=\dfrac{1}{2}\times 0.12\ kg\times (5.385\ m/s)$

E = 1.739 J

or

E = 1.74 J

So, the kinetic energy of the object is 1.74 Joules. Hence, this is the required solution.

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