Question

A 120kg sprinkle is travelling at 9m/s. What is the momentum of this runner?

Answer 1

Answer:

$p =108 0 \: kg \: m {s}^{ - 1}$

Explanation:

$momentum = p = mass \times velocity \\ p = 120 \times 9 \\ p =108 0 \: kg \: m {s}^{ - 1}$

Answer 2

Answer:

1080j hope if will help you