Question

a= 125 b=125 c= 152 solve by herons formula ?
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Answer 1

Answer:

If a = 125 b = 125 and c= 152, then the area of the circle is 532√201 sq. unit.

Step-by-step explanation:

a = 125 , b = 125 and c = 152

S= (a + b+ c)/2

= (125 + 125 + 152)/2

= 402/2

= 201

Area of circle = $\sqrt{s(s- a)(s -b) (s -c)}$

[tex]=\sqrt{201(201- 125)(201 -125) (201 -152)} \\ =\sqrt{201 \times 76\times 76\times 49} \\ = 76 \times 7\sqrt{201} \\ = 532\sqrt{201} [/tex]

So, the area of the circle is 532√201 sq. unit.

Answer 2

Answer:

The required value will be $532\sqrt{201}$

Step-by-step explanation:

In accordance with the information provided in the question,

Given the data in question  a= 125 b=125 c= 152

Given

$a=125 ,b =125 ,c =152$

So, the formula is used [tex]s=\frac{a+b+c}{2} \\ [/tex]

Put the value at formula

[tex]\frac{125+125+152}{2} \\ s=\frac{402}{2} \\ s=201[/tex]

Area of circle =

[tex]\sqrt{s(s-a)(s-b)(s-c)} \\ \sqrt{201(201-125)(201-125)(201-152)} \\ \sqrt{201\times 76 \times 76 \times 49} \\ 76\times 7\sqrt{201} \\ 532\sqrt{201} [/tex]

Hence the required value will be $532\sqrt{201}$