a 12g bullet is accelerated from rest to a speed of 700 m/s as it travels 20cm in a gun barrel . Assuming the acceleration to be constant , how large was the accelerating force?
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initial velocity (u) = 0
final velocity (v)= 700m/s
distance covered (s)= 20cm
=20/100 = 0.2m
let's find acceleration using 3rd equation of motion
2as = v^2 - u^2
2 (a)(0.2) = (700)^2 -(0)^2
0.4a = 4900
a = 4900/0.4
= 12250m/s^2
so the acceleration = 12250m/s^2
mass of the bullet=12g
= 12/1000kg
force = mass × acceleration
= (12/1000)×12250
= 47 N
so, the accelerating force was 47N.
final velocity (v)= 700m/s
distance covered (s)= 20cm
=20/100 = 0.2m
let's find acceleration using 3rd equation of motion
2as = v^2 - u^2
2 (a)(0.2) = (700)^2 -(0)^2
0.4a = 4900
a = 4900/0.4
= 12250m/s^2
so the acceleration = 12250m/s^2
mass of the bullet=12g
= 12/1000kg
force = mass × acceleration
= (12/1000)×12250
= 47 N
so, the accelerating force was 47N.
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