Physics, asked by anamika3742, 7 months ago

A 12kg box starts at rest and reaches a velocity of 3.45ms after traveling a distance 12m. What was the force on the box?

Possible Answers:

24.19N

0.041N

2.95N

5.95N

0.496N

Answers

Answered by Anonymous
5

Correct answer:

5.95N

Explanation:

The formula for force is F=ma.

We are given the mass, but we will need to calculate the acceleration to use in the formula.

We know the initial velocity (zero because the box starts from rest), final velocity, and distance traveled. Using these values, we can find the acceleration using the formula v2f=v2i+2aΔx.

Plug in our given values and solve for acceleration.

v2f=v2i+2aΔx

(3.45ms)2=(0ms)2+2a(12m)

11.9m2s2=a(24m)

Divide both sides by 24m.

11.9m2s224m=a(24m)24m

0.496ms2=a

Now we know both the acceleration and the mass, allowing us to solve for the force.

F=ma

F=12kg∗0.496ms2

F=5.95N

Answered by akbarhussain26
4

Answer:

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