Question

A 12n acts on a 4kg jug of water what Is the resulting acceleration of the jug

Answer 1

F=12n M=4kg. F=ma. a=F/m so
a=12/4=3m/s^2

Answer 2

Answer:

3 m/s²

Explanation:

We have been given that,

12 N force acts on a 4 kg jug of water.

We need to find the resulting acceleration of the jug?

We know that

Force = Mass × Acceleration

Here Mass = 4 Kg

Force  = 12 N

Therefore, Acceleration = $\mathbf{\frac{Force}{Mass}}$

                 Acceleration = $\frac{12}{4}$

                 Acceleration = 3 m/s²

Hence, Acceleration of the jug is 3 m/s²