Science, asked by Dp6, 1 year ago

a 12V battery 6w electric bulb ammeter and plug key are connected in a circuit in series calculate the current flowing in the circuit and calculate the resistance of the bulb

Answers

Answered by AgentAV
3
P = VI
So 6= 12 × I
I = 0.5
Current is 0.5 A

V= IR
R = V/I
R= 12/0.5
R= 24 Ohm
I think it's correct now


HimaniVarshney: just correct that..
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AgentAV: thnx
HimaniVarshney: coorect....
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Answered by HimaniVarshney
3

Here is your answer...

v = 12v \\ p = 6w \\ p = iv \\ i =  \frac{p}{v}  \\ i =  \frac{6}{12}  \\ i =  \frac{1}{2}  = 0.5a \\

v = ir \\ r =  \frac{v}{i}  \\ r = \frac{12}{ \frac{1}{2} }  \\ r = 12 \times 2 \\ r = 24 \: ohms.

Thanks..

hope it helps you


Dp6: thanks
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