a=13 b=14 c=15 find circumradius
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semi-perimeter=(13+14+15)/2=42/2=21,
∆=√[21×(21-13)(21-14)(21-15)],
∆=√[21×8×7×6],
∆=√[3×7×4×2×7×2×3],
∆=7×3×2×2=84 units ²,
R=abc/4.∆,
R=(13×14×15)/(4×84),
R=8.125 unit
∆=√[21×(21-13)(21-14)(21-15)],
∆=√[21×8×7×6],
∆=√[3×7×4×2×7×2×3],
∆=7×3×2×2=84 units ²,
R=abc/4.∆,
R=(13×14×15)/(4×84),
R=8.125 unit
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Answer:8.125
Step-by-step explanation:Formula for circumradius is abc/4×area of triangle.
Area(heron's formula) : under root of S(S-a)(S-b)(S-c).
Therefore area=root over 21(8×7×6) where s=a+b+c/2
=84
Hence circumradius =13×14×15/4×84
=8.125
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