|a| =13 |b| = 5 and a.b = 60 then |a*b| is
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Answer:
cos theta=a.b/|a| |b|
cos theta=60/(13)(5)
=60/65
=12/13
then sin theta = √1-cos² theta
sin theta = √1-(12/13)²
sin theta=5/13
NOW
|a×b|=|a||b| sin theta
=13×5×5/13
=5×5
=25
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