Math, asked by snehlatakagla, 11 months ago

a 13 foot ladder is leaning against a vertical wall . The lowest point of the ladder is 4 feet from the wall. what is the height of the point where the ladder touches the wall ? (Round your answer to the nearest tenth of a foot.)​

Answers

Answered by jeetuverma13jp
7

Length of ladder = hypotenuse

H^2=p^2+b^2

13^2=p^2+4^2

169=p^2+16

P^2=153

P=√153

Answered by BrainlyConqueror0901
19

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\therefore{\text{Height\:of\:wall=12.36\:feet}}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

• In the given question information given about a 13 foot ladder is leaning against a vertical wall . The lowest point of the ladder is 4 feet from the wall.

• We have to find the height of the point where the ladder touches the wall.

 \green{\underline \bold{Given :}} \\ : \implies \text{Length\:of\:ladder=13\:feet} \\ \\ : \implies \text{Distance\:between\:wall\:and\:foot\:of\:ladder=4\:feet}\\\\  \red{\underline \bold{To \: Find:}} \\ : \implies \text{Height\:of\:wall=  ?}

• Accroding to given question :

  \bold{ By \: pythagoras \: theorem} \\    :  \implies  {h}^{2}  =  {p}^{2}  +  {b}^{2}  \\  \\   : \implies   {AC}^{2}  =  {AB}^{2}  +  {BC}^{2}  \\  \\   : \implies  {13}^{2}  =  {AB}^{2}  +  4^{2}  \\  \\   : \implies   {AB}^{2} =169-16\\  \\   : \implies  {AB}^{2} =153 \\  \\   : \implies AB=  \sqrt{153}  \\  \\  \green{: \implies  \text{AB = 12.36\: feet}}

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