A 13-foot ladder slants against a building. The foot of the ladder is 5 feet away from the base of the building. How far up the side of the building does the ladder reach?
Answers
Answer:
Step-by-step explanation:
The ladder forms a right angled triangle with the wall and the base with length of the ladder being the length of hypotenuse of this triangle.
Hypotenuse =25 m
Base =7 m
Height =25
2
−7
2
=24 m
Now the ladder slides. In the new position, the hypotenuse of the new right angled triangle will be the same.
The top slides down by a distance 4m. Hence, the height is 24−4=20 m. Let the base slide by a distance x. Therefore, hypotenuse =25 m
Base =(7+x) m
Height =20 m
By Pythagoras Theorem, we get
25
2
−20
2
=(7+x)
2
∴(7+x)=15
Hence, x=8
The correct answer is Option B.
Answer:
Here,
Height of ladder=13 feet
Distance between base of building and ladder=5 feet
Now, it is right triangle
so,
13^2-5^2=Ladder reaches ^2 ( Pythogoras theorem)
144=ladder reaches^2
=>Ladder reaches= 12 feet
Hence the answer is 12 feet.
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