Question

a) 13(x + 20) = 39
b) 10(x-2)-4(x+1)+3(x+6)=0
c)2{(x+1)+(x+2)}={(x+3)+(x+4)}​

Answer 1

Step-by-step explanation:

(i) 13(x + 20) = 39

→ 13x + 260 = 39

→ 13x = 39 - 260

→ 13x = - 221

→ x = - 121/13

→ x = -17

(ii) 10(x-2)-4(x+1)+3(x+6)=0

→ 10x - 20 - 4x - 4 + 3x + 18 = 0

→ (10x + 3x - 4x) + (18 - 20 - 4) = 0

→ 9x + ( -6) = 0

→ 9x - 6 = 0

→ 9x = 6

→ x = 6/9

→ x = ⅔

(iii) 2{(x+1)+(x+2)}={(x+3)+(x+4)}

→ 2{ x + 1 + x + 2 } = { x + 3 + x + 4 }

→ 2{2x + 3} = { 2x + 7 }

→ 4x + 6 = 2x + 7

→ 4x - 2x = 7 - 6

→ 2x = 1

→ x = ½

Answer 2

Answer:

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Here is Your Answer...!!

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Step by step solution:

a.

13(x + 20) = 39

13x + 260 = 39

13x = 39 - 260

$x=\frac{-221}{13}=-17$

b.

10(x - 2) - 4(x + 1) + 3(x + 6) = 0

10x - 20 - 4x - 4 + 3x + 18 = 0

10x + 3x - 4x = 24 - 18

9x = 6

$x=\frac{6}{9}=\frac{2}{3}$

c.

2{(x + 1) + (x + 2)} = {(x + 3) + (x + 4)}​

2[x + 1+x + 2] = x + 3 + x + 4

2[2x + 3] = 2x + 7

4x + 6 = 2x + 7

4x - 2x = 7 - 6

2x = 1

$x=\frac{1}{2}$

Hope it is clear to you.