A 130 ohm resistance and a capacitor of 40 microfarads are connected to an ac source with angular frequency 'w'(omega). What is the the minimum value of 'w' for which the circuit is a pure resistive load?
Answers
Given : a 130 ohm resistor and 40uf capacitor are connected in series to an AC source of angular frequency ω
To Find : the value of ω for which the combination acts as a pure resistive load is
Solution:
pure resistive load if XL = Xc
⇒ 2πfL = 1/2πfC
Here only capacitor is given so need to have infinite frequency which is not possible
We need inductor also in the circuit
Then 2πfL = 1/2πfC
ω = 2πf
⇒ ωL = 1/ωC
⇒ ω² = 1/LC
⇒ ω = 1/√LC
To Find the value of ω for which the combination acts as a pure resistive load , we need inductor also in circuit.
Then ω = 1/√LC can be calculated
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Explanation:
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