Question

a 13m long ladder reached a window 12m high from the ground on placing it agaunst a wall at a distance a . find the distance of the foot of the ladder from the wall.

Answer 1

Find out the distance of foot of ladder from the wall .

To prove

As given

A ladder 13 m long reaches a window 12 m above the ground.

By using the pythagorus theorem

Hypotenuse² = Perpendicular² + Base²

As shown the diagram given below .

AB² = AC ²+ CB²

as AB = 13 m ,

AC = 12m

put in the above

13² = 12² + CB²

169 = 144 + CB²

169 - 144 = CB²

25 = CB²

CB =

$\sqrt[]{25}$

CB = 5m

Therefore the distance of foot of ladder from the wall be 5 m .

Answer 2

Step-by-step explanation:

Find out the distance of foot of ladder from the wall .

To prove

As given

A ladder 13 m long reaches a window 12 m above the ground.

By using the pythagorus theorem

Hypotenuse² = Perpendicular² + Base²

As shown the diagram given below .

AB² = AC ²+ CB²

as AB = 13 m ,

AC = 12m

put in the above

13² = 12² + CB²

169 = 144 + CB²

169 - 144 = CB²

25 = CB²

CB =

\sqrt[]{25}

25

CB = 5m