Question

A 13N weight and a 12N weight are connected by a massless string over a massless frictional pulley. the13N weight has a downwards acceleration with magnitude equal to that of a freely falling body times
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Answer 1

Answer:

Explanation:

=> Here, A 13N weight and a 12N weight are connected by a massless string over a massless frictional pulley.

suppose, downward acceleration of 13-N weight and upward acceleration of 12-N weight is 'a'.

=> Let the tension in the string 'T'.

m1 = 13/g

m2 = 12/g

=> Now, For 13N weight (mass):

m1 * a = 13 - T

13/g * a = 13 - T ...(1)

=> For 12N weight (mass):

m2 * a = T - 12

12/g * a = T - 12 ...(2)

=> By adding eq(1) and (2), we get

(13/g * a) + (12/g * a) = (13 - T) + (T - 12)

25/g * a = 13 - T + T - 12

25/g * a = 1

a = 1/25 * g