A (14, – 2), B (6, – 2) and D (8, 2) are the vertices of a parallelogram ABCD. Find the coordinates of the vertex C. Also find the length of diagonal BD.
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Step-by-step explanation:The diagoanls of a parrelogram bisect each other. Lets say that they bisect at O .
O is the midpoint of AC
coordiantes of O = (6+8)/2 , (-2+2)/2
USING MID POINT FORMULA
coordinates of O = (7,0)
Since O is also the mid point of BD
again using MID POINT FORMULA
O= (14+x)/2 , (-2+y)/2.
coordinates of c=(x,y)
7= 14+x÷2 and 0 = -2+y÷2
x=0. y=2
coordinates of C = (0,2)
length of BD = [(8-6)^2 + (2+2)^2]^1/2
= [ 4 +4 ] ^1/2
= 8^1/2
= 2 × 2^1/2
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