Question

A (14, 7), B (6, -3) and C (8, 1) are the vertices of a triangle ABC. P is the midpoint of AB, and Q is the midpoint of AC, Write down the co-ordinates of P and Q. Show that BC = 2PQ. no spamming please ​

Answer 1

Answer:

Step-by-step explanation:

given P is midpoint of AB and Q is the midpoint of AC

P = (10,2)   Q= (11,4)

distance = $\sqrt{(x2-x1)^{2} + (y2-y1)^{2} }$

length of PQ = $\sqrt{(4-2)^{2} + (11-10)^{2} }$  =  $\sqrt{4+1}$  = $\sqrt{5}$

length of BC = $\sqrt{(1-(-3))^{2} + (8-6)^{2} }$ = $\sqrt{16 + 4}$ =$\sqrt{20}$ = $\sqrt{4 * 5}$  = 2$\sqrt{5}$

∴ BC = 2PQ