Question

A 140 g ball, in horizontal flight with a speed of
39.0 m/s, is struck by a bat. After leaving the bat,
the ball travels in the opposite direction with speed
v, = 39.0 m/s. If the impact time At for the ball-
bat collision is 1.20 ms, what average force acts on
the ball ?
(1) 1308 N
(2) 1090 N
(3) 9100 N
(4) 980 N​

Answer 1

The average force acting on  the ball is 9100 N.

Explanation:

It is given that,

Mass of the ball, m = 140 g = 0.14 kg

Initial speed of the ball, u = 39 m/s

Final speed of the ball, v = -39 m/s (negative as the ball travels in the opposite direction)

Time of collision, $t=1.2\ ms=1.2\times 10^{-3}\ s$

Let F is the average force acts on  the ball. It is given by :

$F=ma$

$F=m\times \dfrac{v-u}{t}$

$F=0.14\ kg\times \dfrac{(-39-39)\ m/s}{1.2\times 10^{-3}\ s}$

F = -9100 N

or

|F| = 9100 N

So, the average force acting on  the ball is 9100 N. Hence, this is the required solution.

Learn more,

Second law of motion

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