Question

a 14cm long chord subtends a right angle at the centre of its circle. find the area of corresponding sector of circle ​

Answer 1

Answer:

Given radius(r)=14cm

⇒  Area of sector OABO=  $\frac{0}{360} \degree\:\pi r^{2}$

∴  Area of sector OABO=  

$\frac{90 ^o}{360 ^o} \frac{22}{7} (14) ^2 =154cm ^2$

⇒  Area of right angled △OAB=  

$\frac{1}{2} ×14×14=98cm ^2$

∴  Area of the minor segment of the circle = Area of sector OABO - Area of right angled △ABO

∴  Area of the minor segment of the circle $=(154−98)cm ^2$

$=56cm ^2$

 ⇒  Area of circle =πr  ^2

$=\frac{22}{7} ×14×14=616cm ^2$

⇒  Area of the major segment of the circle = Area of circle - Area of minor segment.

∴  Area of the major segment of the circle $=(616−56)cm ^2 =560cm ^2$

 

Step-by-step explanation: