Question

A 15-m ladder is placed against a wall in such a way that the foot of the ladder is 9 metre away from the wall. At what height does the ladder reach the wall?​

Answer 1

FOR FIG. SEE THE IMAGE...

in triangle

${bc}^{2} = {ac}^{2} + {ab}^{2}$

${15}^{2} - {9}^{2} = {ab}^{2}$

$225 - 81 = {ab}^{2}$

$13 = ab$

hence this is the height if wall.

#bal

#answerwithquality

Answer 2

Answer:

12 m is your answer

Step-by-step explanation:

Let height of the wall =AB

Foot of the ladder from the wall=AC

Length of ladder=BC

AB^2=BC^2 - AC^2

AB^2=(15)^2 - (9)^2

AB^2=225 - 81

AB^2=144

AB=(144)^1/2

AB=12

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