Question

A 15 m ladder reaches a wall which is 12m high. How far is the foot of the ladder from the wall?

Answer 1

Answer:

distance =√(15)^2-(12)^2

=√(225-144

=√(81)

=9m

hope it helps u..❤..

Answer 2

Answer= 9 m

${\red{\huge{\underline{\mathbb{solution:-}}}}} \\ \\ by \: pythagoras \: theorem \\ \\ {(15)}^{2} = {(12)}^{2} + {(distance)}^{2} \\ \\ 225 = 144 + {(distance)}^{2} \\ \\ {(distance)}^{2} = 225 - 144 \\ \\ distance = \sqrt{81} \\ \\ distance = 9 \\ wall \: is \: far \: away \: from \: the \: ladder \: by \: 9 \: metre.$

hope it's helpful