Question

A 15 m long is placed against a wall to reach a window. 12m high . find the distance of the foot of the ladder fron the wall.​

Answer 1

Answer:

Let BC be the wall and AB be the ladder. Then, AB = 15 m and BC = 12 m. Now, ΔABC being right-angled at C, we have: AB2 = BC2 + AC2 AC2 = (AB2 – BC2) AC2 = (152 – 122) AC2 = (225 – 144) AC2 = (81) Sending power 2 from LHS to RHS it becomes square root AC = √(81) AC = 9 cm ∴The distance of the foot of the ladder from the wall is 9 cmRead more on Sarthaks.com - https://www.sarthaks.com/752732/long-ladder-placed-against-wall-reach-window-high-find-distance-foot-the-ladder-from-wall

pls Mark me as the brainlest

Answer 2

Answer:

we have to find the base.

by using Pythagoras theorem

(15)²=(12)²+(B)²

225=144+B²

81=B²

B=√81

B=9

Step-by-step explanation:

Please Subscribe our channel THE HIT DUDE