Question

A 15- m -long ladder is placed against a wall to reach a window 12 m high . find the distance of the foot of the ladder from the wall.

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Answer 1

Answer:

Let triangle be abc. then AC is ladder, about is wall and the line by is distance between ladder and wall

by Pythagoras formula

(AC) ^2=(ab) ^2 +(be) ^2

225=144+x^2

x^2= 225-144=81

x= 9(distance)

Answer 2

✬ Distance = 9 m ✬

Step-by-step explanation:

Given:

• Length of ladder is 15 m.
• Height of window from ground is 12 m.

To Find:

• What is the distance of foot of ladder from wall ?

Solution: Let AB be a ladder of 15 m , BC be the window of height 12 m & AC be the foot of ladder from window.

Now, In ∆ABC right angled at C we have :-

• AB = 15 m ( Hypotenuse )
• BC = 12 m ( Perpendicular )
• AC = ( Base )
• ∠ACB = 90°

Apply Pythagoras Theorem in ∆ABC

★Pythagoras Theorem → H² = B² + P²★

$\implies{\rm }$ AB² = AC² + BC²

$\implies$ 15² = AC² + 12²

$\implies$ 15 $\times$ 15 = AC² + 12 $\times$ 12

$\implies$ 225 = AC² = 144

$\implies$ 225 – 144 = AC²

$\implies$ 81 = AC²

$\implies$ √81 = AC²

$\implies$ √9 $\times$ 9 = AC²

$\implies$ 9 cm = AC

Hence, the distance of the foot of ladder from wall is AC = 9 cm.