A 15 m long ladder is placed against a wall to reach a window 12m gh. Find the distance of the foot ladder from the wall
Answers
Answered by
3
let the arrangement be a right angled triangle in which ladder is the hypotenuse=15m
height of window is the altitude =12 m
and we are required to calculate the distance of the foot from wall which is the base of the triangle
so A/Pythagoras theorem.
b=√(h^2-a^)
so, b=√(15^2-12^2)=9 m ans.
Thanks
height of window is the altitude =12 m
and we are required to calculate the distance of the foot from wall which is the base of the triangle
so A/Pythagoras theorem.
b=√(h^2-a^)
so, b=√(15^2-12^2)=9 m ans.
Thanks
Answered by
8
Heya ☺
Let the the given condition be in the form of a right - angled triangle. Then,
By Pythagoreous theorem
H = 15 m
P = 12 m
B = ?
H^2 = P^2 + B^2
=> (15)^2 = (12)^2 + B^2
=> 225 = 144 + B^2
=> 225 - 144 = B^2
=> 81 = B^2
=> B = √81
=> B = 9 m
Hence , the distance of the foot ladder from the wall is 9 m.
Thanks
Let the the given condition be in the form of a right - angled triangle. Then,
By Pythagoreous theorem
H = 15 m
P = 12 m
B = ?
H^2 = P^2 + B^2
=> (15)^2 = (12)^2 + B^2
=> 225 = 144 + B^2
=> 225 - 144 = B^2
=> 81 = B^2
=> B = √81
=> B = 9 m
Hence , the distance of the foot ladder from the wall is 9 m.
Thanks
Similar questions