Question

A 15 m long ladder reached a window 12 m high from the ground on placing it against a wall at a distance a. find the distance of the foot of the ladder from the wall.* *
​

Answer 1

Question :-

A 15m long ladder reached a window 12m high from the ground on placing it against a wall at a distance a. Find the distance of the foot of the ladder from the wall.

Answer :-

Let AC be the ladder and A be the window.

Given :-

• AC=15m, 

• AB=12m, 

• CB=am

In right angled triangle ACB,

Hypotenuse²=Base²+Perpendicular²

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀__{By Pythagoras theorem}

Now ,

Putting all values ;

(AC)²=(CB)²+(AB)²

(15)²=(a)²+(12)²

225=a²+144

a²=225−144

a²=81

⠀⠀⠀⠀⠀⠀⠀⠀Taking square root

a=√81

a=9

So,

a=9cm

Thus, the distance of the foot of the ladder from the wall is 9m.