Question

a 15 m long ladder reached a window 12m high from the ground on placing it against a wall at a distance x find the distance of the foot of the ladder from the wall​

Answer 1

Answer:

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Step-by-step explanation:

15 × 12=Let BC be the wall and AB be the ladder

Then, AB=15cm and BC=12m

Now, △ABC being right-angled at C we have

AB2=BC2+AC2

AC2=AB2−BC2

AC2=152−122

AC2=81

Senidng power 2 from LHS to RHS it becomes square root

AC=81

AC=9cm

The distance of the foot of the ladder from the wall is 9cm