A 15 m long ladder reached a window 12m high from the ground on placing it aganista wall at a distance 'a'. Find the distance of the foot of ladder from the wall
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Answer:
Step-by-step explanation:
h =15 m
P= 12 m
p²+b²= h² ( pythagoras theorem)
(12)²+b²= (15)²
144+b²= 225
b²= 225-144
=81
b=9 cm
thus , distance of foot of ladder from wall = 9 cm ans
Answered by
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let the height of the ladder be AB
AB= 15m
and
distance of the window from the ground be AC
AC = 12m
Now
In right angled triangle ABC
By Pythagoras theorem
AB²= AC²+BC²
15²= 12²+BC²
225= 144+BC²
BC²=225-144
= 81
BC=9m
thus
distance of the foot of ladder from the wall is 9m
❤️❤️ hope it helped
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