A 15 m long ladder reached a window 8 m high from the ground on placing it against wall at a distance a . find the distance of the foot of ladder from the wall
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Hi ,
Draw the rough diagram which shows the details of the problem
Diagram shows a right angled triangle ABC . Right angle at
Let the length of ladder AC = 15 m ( hypotenuse )
Angle between ladder and wall < BCA= 60 degrees
Angle between ladder and the ground < CAB = 90 - 60 = 30 degrees
Height of the wall = BC
From triangle ABC,
Sin
Sin 30 = BC / 15
1 / 2 = BC / 15
15 / 2 = BC
7.5 = BC
Therefore,
Height of the wall = BC = 7.5 m
I hope this will useful to you.
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