Question

A 15 m long ladder reached the window 12 m high from the ground against the wall a. Find the distance of the foot of the ladder from the wall ​​

Answer 1

By Pythagoras theorem,  

(15)²=(12)²+distance ²

225=144+distance ²

225-144=81=distance²

√81=distance

9 = distance

Wall is far away from the ladder by 9 metre

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Answer 2

Let AC be the ladder and A be the window.

Given : AC = 15, AB = 12, CB = am

In right angle triangle ACB,

( hypotenuse)² = ( base)² + [ perpendicular)²

By Pythagoras theorem]

= (AC)² = (CB)² + (AB)²

= (15)² = (a)² + (12)²

= 225 = a² + 144

= a² = 225 - 144 = 81

= a = √81 = 9cm

Hence the distance of the foot of the ladder from the wall is 9cm.