A 15 m long ladder reaches a window 12 m high from
the ground on placing it against a wall. How far is the foot
of the ladder from the wall? ( Draw diagram and solve)
Answers
Answered by
0
Answer:
9m
Step-by-step explanation:
The diagram is attached above.
It forms right angle triangle so AC² = AB² + BC²
= 15² = 12² + BC²
BC² = 15² - 12² = 225 - 144 = 81
BC² = 81
BC = √81 = 9
Therefore the length between foot of the ladder and the wall is 9m.
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Attachments:
Answered by
0
Answer:
9 m of ground
Step-by-step explanation:
Lenth of ledder = 15m
widow = 12m
15m is hypotnuse , 12m is prependicular
so
(H)^2 = (P)^2 + (B)^2
15^2 = 12^2 + (B)^2
225 = 144 + B^2
225-144 = 81 =B^2
sq. root of 81 = B = 9
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