Math, asked by rejijogy, 12 hours ago

A 15 m long ladder reaches a window 12 m high from

the ground on placing it against a wall. How far is the foot

of the ladder from the wall? ( Draw diagram and solve)​

Answers

Answered by arjun18436
0

Answer:

9m

Step-by-step explanation:

The diagram is attached above.

It forms right angle triangle so AC² = AB² + BC²

= 15² = 12² + BC²

BC² = 15² - 12² = 225 - 144 = 81

BC² = 81

BC = √81 = 9

Therefore the length between foot of the ladder and the wall is 9m.

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Attachments:
Answered by ayansharma125114
0

Answer:

9 m of ground

Step-by-step explanation:

Lenth of ledder = 15m

widow = 12m

15m is hypotnuse , 12m is prependicular

so

(H)^2 = (P)^2 + (B)^2

15^2 = 12^2 + (B)^2

225 = 144 + B^2

225-144 = 81 =B^2

sq. root of 81 = B = 9

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