Question

A 15 % (m/m) aqueous solution of glucose is prepared by dissolving 13.5 g of glucose in x g of water. Calculate the value of x. ​

Answer 1

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Explanation:

Osmotic pressure is proportional to the molarity, C, of the solution at a given temperature T. Thus

...(i)

Where,

П= osmotic pressure

R= gas constant =0.0821dm

3

atm mol

тут

−1

T= temperature =298K

C= molarity =

V

n

=

MxV

W

...(ii)

Where,

n= no. of moles

w= Weight of solute glucose =4.5g

M= Molecular weight of solute glucose =180g

V= Volume of solution =100ml=0.1L

Putting the values in the formula (i) and (ii) we get :

π=

MV

WRT

=

180×0.1

4.5×0.0821×298

18

110.09

=6.12atm

The osmotic pressure of the solution is 6.12atm.

Answer 2

Explanation:

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Explanation :

Osmotic pressure is proportional to the molarity ,C, of the solution at a given temperature T. thus