Question

A
15
meters
long
ladder
reached
a


window
12
meters
high
from
the
ground


on
placing
it
against
a
wall
at
a
distance


‘q’
meters
from
the
foot
of
ladder.
Find


the
distance
(q)
of
the
foot
of
the
ladder


from
the
wall.​

Answer 1

Step-by-step explanation:

Let AC be the ladder and A be the window.

Given: AC=15m, AB=12m, CB=am

In right angled triangle ACB,

(Hypotenuse)

2

=(Base)

2

+[Perpendicular)

2

[By Pythagoras theorem]

⇒(AC)

2

=(CB)

2

+(AB)

2

⇒(15)

2

=(a)

2

+(12)

2

⇒225=a

2

+144

⇒a

2

=225−144=81

⇒a=

81

=9cm

Thus, the distance of the foot of the ladder from the wall is 9m.

solution