Question

a 15 metre long ladder rich a windows 12 hight from the ground on placing it against a wall at distance of the foot of the leader from the wall​

Answer 1

the distance of the foot of the ladder from the wall is 9m.

Answer 2

Step-by-step explanation:

With full explanation

Let AC be the ladder and A be the window.

Given: AC=15m, AB=12m, CB=am

In right angled triangle ACB,

(Hypotenuse)²=(Base) ²

+ (Perpendicular)²

[By Pythagoras theorem]

⇒(AC)² = (CB)² +(AB)²

⇒(15)² = (a)² +(12)²

⇒225 = a² +144

⇒a² =225−144=81

$a = \sqrt{81} \: = 9$

Thus, the distance of the foot of the ladder from the wall is 9m.

Hope it helps