Question

A 150 g ball, travelling at 30 m/s, strikes the palm of a player’s hand and is stopped in 0.05 second. Find the force exerted by the ball on the hand.

Answer 1

Answer:

Given:

m=150g=0.15kg

u=30m/s

v=0m/s

t=0.05sec

F=mxa

=0.15 * (v-u)/t

=0.15*(0-30)/0.05

=3 x -30

=-90N

Explanation:

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Answer 2

Explanation:

Given:

m=150g=0.15kg

u=30m/s

v=0m/s

t=0.05sec

F=mxa

=0.15 * (v-u)/t

=0.15*(0-30)/0.05

=3 x -30

=-90N