A 150 g ball travelling at 30 m/s strikes the palm of a player's hand and is stopped in 0.06 seconds. Calculate the force exerted by the ball on the hand.
(d) - 75 N
(a) 75 N
(c) - 750 N
(b) 750 N
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Answer:Given:
m=150g=0.15kg
u=30m/s
v=0m/s
t=0.05sec
F=mxa
=0.15 * (v-u)/t
=0.15*(0-30)/0.05
=3 x -30
=-90N
hope it helps u
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