A 150 g baseball is traveling horizontally at 50 m/s. If the ball takes 20 ms to stop once it is in contact with the catcher’s glove, what average force did the ball exert on the catcher?
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m = 150 g = 0.15 kg
u = 50 m/s
v = 0
t = 20 ms = 0.02 s
F = ?
A/T 2'nd law of motion
F = ma
or F = m * (v-u)/t [ v = u + at]
or F = 0.150 * (0-50)/0.02
or F = 0.150 * (-50/0.02)
or F = 0.150 * (-2500)
or F = 375 N
u = 50 m/s
v = 0
t = 20 ms = 0.02 s
F = ?
A/T 2'nd law of motion
F = ma
or F = m * (v-u)/t [ v = u + at]
or F = 0.150 * (0-50)/0.02
or F = 0.150 * (-50/0.02)
or F = 0.150 * (-2500)
or F = 375 N
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