Question

A 150 g cricket ball moving at a speed of 12 m s-1 is
hit by a bat and turned back at a speed of 20 m s-1.
The duration of impact is 0.01 s. What is the average
force exerted on the ball by the bat?​

Answer 1

Given :

m = 150

g = 0.15 kg,

u = 12 m/s^-1

v= -20 m/s^-1

t = 0.01 s,

To find :

F = ?

Solution :

As,

➸ F x t = Impulse = change in momentum

➸ F x 0.01

➸ m (v - u)

➸ 0.150 (- 20 - 12)

➸ F = -0.15 x 32/0.01

➸ F = - 480N

Answer 2

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✒Given:

We have been given that the mass of the ball is 150gm.

It is moving with a velocity of 12m/sec.

When it was hit witg a bat, it turned back with a velocity of 20m/sec.

✒To Find:

We need to find the impulse of the ball.

Solution:

We have been given that the mass of the ball(m) is 150g.

✒We know that 1gm = 0.001kg

∴150gm = 0.15kg

Also, the initial speed of the ball (u) is -12m/s.

Now, final speed of the ball after being hit with a bat is 20m/s.

Impulse = change in momentum

= 0.15 × 20 0.15 × (-12) = 4.8Ns

$\huge \orange{\rm{Hence \: we \: Are \: Done !!}}$