Question

A 150 g tennis ball coming at a speed of 40m/s is hit straight back by a bat to speed 60 m/s.The magnitude of the average force F on the ball,when it is in contact for 5ms with bat is ......?

Answer 1

Answer:-

→ Force = 600 N

Step - by - step explanation :-

To find :-

Find the magnitude of average force .

Given:-

Final velocity (v2)= 60 m/s

Initial velocity (v1)= 40 m/s

Mass of ball (m) = 150 g = 0.15 kg

Time(t)=5 Mili seconds=5/1000 seconds,

Solution :-

We know that,

$\bf{acceleration \: = \frac{change \: in \: velocity}{time} } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \bf{ \frac{(60 - 40)}{ \frac{5}{1000} } \: \frac{m}{ {s}^{2} } } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf{ = 4000 \: \frac{m}{ {s}^{2} } }$

Now ,we know that,

$\because \: \red{\bf{ by \: the \: newtons \: second \: law}}$

→Force = mass × acceleration

$\bf{force \: = 0.15 \times 4000} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf{ = 600 \: newton}$

Answer 2

Answer:

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