A 150 meters long through train having a constant accleration crosses a 300 m long platform. It enters the platform at a speed of 40ms-1and leaves it at a speed of 50ms-1 . What is the acceleration of train
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Explanation:
Total distance covered by the Train = 300 + 150
= 450 m.
Initial velocity of the train = 40 m/s.
Final velocity of the train = 50 m/s.
Using the formula,
v² - u² = 2aS,
where a is the acceleration of the Train.
Substituting the value in the given equation, we will get,
(50)² - (40)² = 2a(450)
2500 - 1600 = 900a
900 = 900a
∴ a = 1 m/s².
Hence, acceleration of the train is 1 m/s².
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