a 1500kg car is moving with a speed of 50m/s . when brakes are applied it stops with uniform retardation atva distance of 150m. calculate the force applied by brakes of the car and work done before stopping
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Answered by
4
Answer:
12500 N
Explanation:
m = 1500 kg
s = ut + 1/2 axtxt
150 = 50t + 1/2 x v-u/t x t x t
150= 50t + 1/2 x -50t
150 = 50t -25t
150/25 =t
t = 6 s
F = ma
= 1500 x v - u /t
= 1500 x -50 / 6
= 12500 N
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1
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